Question 1062397
It is D.  CB is 1:12 of AB
1.24568 is 1/12th of 14.94816.
We want a ratio of CB/AB, and that is sine
Therefore arc sin 1.24568/15= the angle sin^(-1)CB/AB
And the angle is 4.76 degrees.
In the instance where the slope is 1:12, the hypotenuse is sqrt (1^2+12^2)=sqrt (145)
The arc sin of 1/sqrt (145)=4.76 degrees