Question 1062396
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a boy has 728 rs denomination of 2 rs notes,5 rs notes and 10 rs nots in the ratio of 3:2:4,respectively. what is the number of notes he has?
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The condition says that the numbers of bills are

   3x for 2-rs notes,
   2x for 5-rs notes, and
   4x for 10-rs notes,

where x in an unknown "common measure" of these quantities (of bills).

Then your "value" equation is

  2*(3x) + 5*(2x) + 10*(4x) = 728,   or

  6x + 10x + 40x = 728,   or

  56x = 728.

Then x = {{{728/56}}} = 13.

Thus there are 3*13 = 39 of the 2-rs notes, 2*13 = 26 of the 5-rs notes and 4*13 = 52 of the 10-rs notes.
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Solved.