Question 1062324
x2 - 10x + y2 + 4y + 13 = 0
Use ^ (Shift 6) for exponents.
x^2 - 10x + y^2 + 4y = -13
a. Find the corresponding standard form
complete the square for x, and for y.
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b. Identify the center and radius of the circle
(x-h)^2 + (j-k)^2 = r^2
Center at (h,k), radius = r
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c. Find the x- and y-intercepts
x-ints at y = 0, y-ints @ x = 0 (if any)
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d. Graph the circle