Question 1062257
Three red pens,
{{{P=(6/9)(5/8)(4/7)=5/21}}}
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Look at the possible outcomes,
RRB
RBR
BRR
There are three of them so,
{{{P=3(6/9)(5/8)(3/7)=15/28}}}
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We'll do this one backwards.
Find the probability of no blue pens or only one blue pen,
No blue pens would be all red from above, {{{P=5/21}}}
One blue pen would be the second answer, {{{P=15/28}}}
So then no blue pens or one blue pen would be,
{{{P=5/21+15/28=20/84+45/84=65/84}}}
So then the complement of that probability is your answer,
{{{P=1-65/84=84/84-65/84=19/84}}}