<PRE><B>Question 1062258</B>
2, 9, 27, 65
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each member of this series is the sum of the digits of n^3
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a10 = sum of the digits of 10^3 = 1
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Note that 10^3 = 1000 and the sum of its digits is 1
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Note that 2 is the 11th term and the sequence begins at 0
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3(n+1) gives 6, 9, 12, 15 for n = 1, 2, 3, 4
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