Question 1062230
Hi there,
Consider your problem as a right angled triangle.
Depth of submarine = opposite side = 2.3 metres
Angle of Depression = 25.6 degrees.
Horizontal distance of ship = Adjacent side.
Tan = Opposite/Adjacent
Tan(25.6) = 2.3/Adjacent
Cross multiply
Adjacent x Tan(25.6) = 2.3
Adjacent = 2.3/Tan(25.6)
Adjacent = 4.8 metres.
Horizontal distance = 4.8 metres.
Hope this helps :-)