Question 1062214
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Could you please help me. What is the solution of the equation 2(x+2)^2-4=28 when solved for x. 
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<pre>
{{{2(x+2)^2-4}}} = 28,

{{{2(x+2)^2}}} = 28 + 4 = 32,

{{{(x+2)^2}}} = {{{32/2}}} = 16,

x + 2 = +/-{{{sqrt(16)}}} = +/-4.

x = -2 + 4 = 2  OR  x = -2 - 4 = -6.

<U>Answer</U>. The solutions are -6 and 2.
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