Question 1062200
Write the point slope form of the equation of the 
line that passes through the points (-3,5) and (-1,4)
<pre><font size=4><b>

Let's plot the points (-3,5) and (-1,4), and draw a line
through them (in green):

{{{drawing(300,300,-5,5,-2,8,graph(300,300,-5,5,-2,8),
locate(-2.5,4,"(-1,4)"), green(line(-9,8,9,-1)),
locate(-4.5,5,"(-3,5)"),circle(-1,4,.05),circle(-1,4,.06),
circle(-3,5,.05),
circle(-3,5,.06) )}}}

Now we use the slope formula:

{{{m}}}{{{""=""}}}{{{(y[2]-y[1])/(x[2]-x[1])}}}

{{{m}}}{{{""=""}}}{{{((4)-(5))/((-1)-(-3))}}}

{{{m}}}{{{""=""}}}{{{(4-5)/(-1+3)}}}

{{{m}}}{{{""=""}}}{{{(-1)/2}}}

{{{m}}}{{{""=""}}}{{{-1/2}}}

Now use the point-slope form:

{{{y-y[1]}}}{{{""=""}}}{{{m(x-x[1])}}}

{{{y-5}}}{{{""=""}}}{{{expr(-1/2)(x-(-3)^"")}}}

That's the point slope form. But it can be simplified 
to the slope-intercept form y = mx+b

{{{y-5}}}{{{""=""}}}{{{expr(-1/2)(x+3)}}}

{{{y-5}}}{{{""=""}}}{{{expr(-1/2)x-3/2}}}

{{{y}}}{{{""=""}}}{{{expr(-1/2)x-3/2+5}}}

{{{y}}}{{{""=""}}}{{{expr(-1/2)x-3/2+10/2}}}

{{{y}}}{{{""=""}}}{{{expr(-1/2)x+7/2}}}

Edwin</pre><b></pre></b>