Question 1062128
> a guy has 120grams worth of candy. If the ten gram sweets are half the number of five gram sweets how many sweets does he have in total?

>solve the simultaneous equation
I) (1/x)+(1/y)=7/10
II)  (3/x)-(5/y)=1/2
<pre>Let number of 10-gram sweets be T
Then number of 5-gram sweets = 2T
We then get: 10T + 5(2T) = 120
10T + 10T = 120
20T = 120
T, or number of 10-gram sweets = {{{highlight_green(matrix(1,3, 120/20, or, 6))}}}
From this, you should be able to determine how many 5-gram sweets there are, and the total number. You shouldn't need my help for that.