Question 1061028
{{{f(-x)=((5(-x)-15)(-x-6))/((-x)^2+18(-x)-19)}}}
{{{f(-x)=((-5x-15)(-x-6))/(x^2-18x-19)}}}
{{{f(-x)=((5x+15)(x+6))/(x^2-18x-19)}}}
So,
{{{f(-x)<>f(x)}}} and
{{{f(-x)<>-f(x)}}}
Neither.