Question 1062135
Let {{{C}}} be the complement, {{{A}}} be the angle,
{{{3C=A-34}}}
and
{{{A+C=90}}}
From the first equation,
{{{A=3C+34}}}
Substituting,
{{{(3C+34)+C=90}}}
{{{4C+34=90}}}
{{{4C=90-34}}}
{{{4C=56}}}
{{{C=14}}}
So then,
{{{A+14=90}}}
{{{A=76}}}