Question 1062060
{{{y[p]=ax+b}}}
{{{dy/dx=a}}}
{{{(d2y)/(dx2)=0}}}
So then,
{{{0+7(a)+12(ax+b)=2x}}}
{{{7a+12ax+12b=2x}}}
{{{12ax+(7a+12b)=2x}}}
So,
{{{12a=2}}}
{{{a=2/12}}}
{{{a=1/6}}}
and
{{{7(1/6)+12b=0}}}
{{{12b=-7/6}}}
{{{b=-7/72}}}
Then,
{{{y[p]=x/6-7/72}}}