Question 93000
{{{((17x-7)/(x^2+3x-4))*((x^2+6x+8)/(2x^2+5x-3))*((x^2+2x)/(x^2+2x-3))}}} Start with the given expression 





{{{(((17x-7))/((x+4)(x-1)))*((x^2+6x+8)/(2x^2+5x-3))*((x^2+2x)/(x^2+2x-3))}}} Factor {{{x^2+3x-4}}} to get {{{(x+4)(x-1)}}}  (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>) 


{{{(((17x-7))/((x+4)(x-1)))*(((x+4)(x+2))/(2x^2+5x-3))*((x^2+2x)/(x^2+2x-3))}}} Factor {{{x^2+6x+8}}} to get {{{(x+4)(x+2)}}}  


{{{(((17x-7))/((x+4)(x-1)))*(((x+4)(x+2))/((x+3)(2*x-1)))*((x^2+2x)/(x^2+2x-3))}}} Factor {{{2x^2+5x-3}}} to get {{{(x+3)(2*x-1)}}}  


{{{(((17x-7))/((x+4)(x-1)))*(((x+4)(x+2))/((x+3)(2*x-1)))*((x(x+2))/(x^2+2x-3))}}} Factor {{{x^2+2x}}} to get {{{x(x+2)}}}  


{{{(((17x-7))/((x+4)(x-1)))*(((x+4)(x+2))/((x+3)(2*x-1)))*((x(x+2))/((x+3)(x-1)))}}} Factor {{{x^2+2x-3}}} to get {{{(x+3)(x-1)}}}  


{{{(((17x-7))/((highlight(x+4))(x-1)))*(((highlight(x+4))(x+2))/((x+3)(2*x-1)))*((x(x+2))/((x+3)(x-1)))}}} Notice we have these common terms


{{{(((17x-7))/((cross(x+4))(x-1)))*(((cross(x+4))(x+2))/((x+3)(2*x-1)))*((x(x+2))/((x+3)(x-1)))}}} They divide and cancel out


{{{((x(17x-7)(x+2)^2)/((x-1)^2(x+3)^2(2*x-1)))}}} Simplify and multiply