Question 92992
Let x=the smallest integer
then x+1 is the next largest 
and x+2 is the largest
x(x+2)=first multiplied by the third and this equals x^2+2x.

Now if he adds the second, he would have:

x^2+2x+x+1 and this turns out to equal 41.  So our equation is:

x^2+2x+x+1=41  subtract 41 from both sides

x^2+2x+x+1-41=41-41  collect like terms

x^2+3x-40=0  quadratic in standard form and it can be factorsd:

(x+8)(x-5)=0

x=-8-----------------NO!!!!  MUST BE POSITIVE

x=5----------------------SMALLEST INTEGER
x+1=5+1=6----------------NEXT LARGEST INTEGER

x+2=5+2=7 --------------LARGEST INTEGER

CK

Multiply 1st by 3rd:  5*7=35

Then add the second:  35+6=41
41=41

Hope this helps----ptaylor