Question 1062041
You can choose 3 faculty members out of 10 eligible in  C(10,3) (=10!/(7!*3!)) ways.

You can choose 5 student members from 15 eligible in  C(15,5) (=15!/(10!*5!) ways.

Since those selections are independent, the total number of committees is just the product of those two numbers.

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          Total committees possible  = C(10,3) * C(15,5) = 120 * 3003 = 360360.
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