Question 1061997
x+3/y+3-x/y=1/15 with x=y-6.  Substitute
(y-6+3)/(y+3)-(y-6)/y=(1/15)
multiply everything by (y+3)(y)(15)
(y-3)(15(y)-(y-6)(y+3)15=y(y+3)
15y^2-45y-15y^2-45y+90y+270=y^2+3y
270=y^2+3y
y^2+3y-270=0
(y+18)(y-15)=0
y=-18,15
x=-24,9
(9,15) is one pair
12/18-9/15=1/15.  That is 2/3-3/5=10/15-9/15=1/15 check
(-24,-18) is the other pair.
That is -21/-15 -(-24/-18)=(7/5)-(4/3)=(21/15)-(20/15)=1/15