Question 1061977

y = (2/3)x - 3
3y = 2x - 9     ( multiplied both sides by 3)
-2x + 3y  = -9    (subtracted 2x from both sides)
-2x + 3y + 9 = 0   (added 9 to both sides)
-2x + 3y + 9 = 0  is standard form of a straight line
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if you prefer the coefficient of x to be positive, you can multiply the above by -1:
2x - 3y - 9 = 0