Question 1061926

An accountant rides a bus part of the way to work every day and walks the rest of the way. The bus averages 35 mph, and the accountant walks at a speed of 6 mph. The distance from home to work is 18 mi, and the total time for the trip 
2 hr. Find how far the accountant walks and how far he rides the bus.
<pre>Let distance he rides the bus, be D
Then distance he walks = 18 – D
Time taken to ride bus: {{{D/35}}}
Time taken to walk: {{{(18 - D)/6}}}
We then get the following TIME equation: {{{D/35  + (18 - D)/6 = 2}}}
6D + 35(18 – D) = 2(210) ------ Multiplying by LCD, 210
6D + 630 – 35D = 420
6D – 35D = 420 – 630
– 29D = - 210
D, or distance he rides the bus = {{{highlight_green(matrix(1,4, (- 210)/(- 29), or, 7&7/29, miles))}}}
Distance he walks: {{{highlight_green(matrix(1,4, 18 - 7&7/29, or, 10&22/29, miles))}}}