Question 92962
{{{3(5^(x+1)) = 15}}}


{{{5^(x+1) = 5}}} Divide both sides by 3


{{{5^(x+1) = 5^1}}} Rewrite 5 as {{{5^1}}}


Now that we have the same base, we can set the exponents equal to each other



{{{x+1=1}}} Set the exponents equal to each other



{{{x=1-1}}} Subtract 1 from both sides





{{{x=0}}} Combine like terms -1 and 1 on the right side to get 0



So our answer is

{{{x= 0}}}


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Check:


{{{3(5^(0+1)) = 15}}} Plug in {{{x= 0}}}


{{{3(5^1) = 15}}} Add


{{{3(5) = 15}}} Rewrite {{{5^1}}}as 5


{{{15=15}}} Multiply.  Since the equations are equal, our answer is verified.