Question 1061634
w and L for the regular field.
w and 2w+9 the  dimensions of the new field.


2L+2w=270, the perimeter of the field (the NEW one?).
If this is the new field, then {{{2(2w+9)+2w=270}}}.
Ready to solve for this new width field.


{{{2w+9+w=135}}}
{{{3w+9=135}}}
{{{3w=126}}}
{{{highlight(w=42)}}} and {{{L=2*42+9=highlight(93)}}} length of new field.