Question 92945
{{{(5a^2/6b)(4b/a^3)}}}


{{{20a^2b/6a^3b}}} Multiply




{{{(10a^2*b)/(3a^3*b)}}} Reduce the coefficients {{{20/6}}} to {{{10/3}}}



 

{{{(10a^(2-3)*b^(1-1))/(3)}}} Now subtract the exponents





{{{(10a^-1*b^0)/(3)}}}



{{{(10b^0)/(3a^1)}}} Flip any negative exponents



{{{(10)/(3a)}}}  Rewrite {{{3a^1}}} as {{{3a}}} and {{{b^0}}} as 1 (which is discarded)