Question 1061542
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One side of an {{{highlight(cross(isoceles))}}} isosceles triangle whose perimeter is 42 units measures 10 units. 
Find the area of the triangle.
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Under the given condition, the sides of the triangle are 10, 16 and 16 units.


The height is {{{sqrt(16^2 - (10/2)^2)}}} = {{{sqrt(256-25)}}} = {{{sqrt(231)}}}.


The area is {{{(1/2)*10*sqrt(231)}}}.