Question 92943
I am not good at these and I am having some problems
Find the x- intercepts
y=x^2-5x-10
X INTERCEPT MEANS WHERE THE LINE MEETS X AXIS...AT THAT POINT Y COORDINATE=0
HENC
X^2-5X-10=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (5 +- sqrt( (-5)^2-4*1*(-10) ))/(2*1) }}} 
{{{x = (5 +- sqrt( 65 ))/(2) }}} 
HENCE X INTERCEPTS ARE 
{{{x = (5 + sqrt( 65 ))/(2) }}} 
AND
{{{x = (5 - sqrt( 65 ))/(2) }}} 

and y=x^2-4x+4 =0
X^2-2*2X+(2)^2=(X-2)^2=0
HENCE X INTERCEPT IS X=2


Thanks you