Question 1061445
Finding {{{I}}} from a "formula" like that is what algebra teachers call "solve for I."
In the formula, {{{I}}} had been manipulated with several operations.
You want to undo what has been done to {{{I}}} .
Since {{{I}}} has been "wrapped" in several layers of algebra,
you want to start unwrapping by removing the last layer applied,
undoing changes in the reverse order that they were applied.
For example, the first thing done to {{{I}}} was subtracting 0.03,
so the last thing you would do would be adding 0.03,
after you have "peeled off all the other algebra layers."
Here is how it goes:
{{{2.4=0.3495*1.03/((I-0.03))}}}
We multiply both sides of the equal sign times {{{(I-0.03)}}} to get
{{{2.4*(I-0.03)=0.3495*1.03}}}
At that point, you can do the multiplication on the right side,
to get {{{2.4*(I-0.03)=0.359985}}} ,
or you can keep "solving" and do all the calculator work at the end.
Next step is dividing both sides of the equal sign by 2.4 to get
{{{I-0.03=0.3495*1.03/2.4}}} or {{{I-0.03=0.359985}}}{{{"÷"}}}{{{2.4=0.149994}}} .
The last step is adding 0.03 to both sides of the equal sign, to get
{{{I=0.3495*1.03/2.4+0.03}}} or {{{I=0.149994+0.03=0.179994}}} .
Now, you have to understand that percentages are ratios,
and {{{"17.999%"=17.999/100=0.17999}}} .