Question 1061321
Starting with your SECOND equation,
{{{x-y+3=0}}}
{{{x=y-3}}}


Substituting for x into the FIRST equation,
{{{highlight(3(y-3)+2y=7)}}}-------the initial result, which can continue until solve for y.


{{{3y-9+2y=7}}}
{{{5y-9=7}}}
{{{5y=7+9}}}
{{{highlight(y=16/5)}}}