Question 1061293
{{{x^2+6x-16=0}}} is factorizable.


{{{(x-L)(x+R)=x^2+6x-16=0}}}

Will 2 and 8 work?  Which of these should be made negative?


{{{(x-8)(x+2)}}}
{{{x^2-8x+2x-16}}}
{{{x^2-6x-16}}}------signs not right.


{{{(x+8)(x-2)}}}
{{{x^2+8x-2x-16}}}
{{{x^2+6x-16}}}------Just like what we were given.


{{{x^2+6x-16=0}}}
{{{(x+8)(x-2)=0}}}

{{{system(x=-8,or,x=2)}}}


<a href="https://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev">See this lesson if you find a quadratic equation that you cannot factorize the quadratic member.</a>


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