Question 92904
this is what you wrote {{{2/sqrt(3)+sqrt(2)}}} ... rationalize by multiplying by {{{sqrt(3)/sqrt(3)}}} ... this gives {{{(2sqrt(3))/3+sqrt(2)}}}


if you meant {{{2/(sqrt(3)+sqrt(2))}}} ... rationalize by multiplying by the conjugate {{{(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))}}} ... this gives {{{(2(sqrt(3)-sqrt(2)))/(3-2)}}} or {{{2(sqrt(3)-sqrt(2))}}}