Question 1061153

Let x = first number
then x+2 = 2nd number

 {{{ x^2 + (x+2)^2 = 202 }}}
{{{  x^2 + (x^2 + 4x + 4) = 202 }}}
{{{   2x^2 + 4x + 4 = 202 }}}
{{{    x^2 + 2x + 2 = 101 }}}
{{{   x^2 + 2x - 99 = 0 }}}
{{{    (x-9)(x+11) = 0 }}}
   
x=9 or x=-11

Problem statement said the numbers are negative,   so x = -11 and  x+2 = -9.  

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Answer:   -11 and -9
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