Question 1061074

Find the vertex and axis of symmetry of the graph of the function.

f(x) = -3x^2 - 6x - 2

    a. (-1, 1) ; x = -1
    b. (2, -26) ; x = 2
    c. (1, -11) ; x = 1
    d. (-2, -8) ; x = -2
<pre>The x-coordinate of the vertex or axis of symmetry occurs at: {{{matrix(1,10, x = - b/(2a), or, "at:", x = - - 6/(2 * - 3), or, "at:", x = 6/- 6, or, "at:", x = - 1))}}} 
The y-coordinate of the vertex occurs at: {{{matrix(1,10, f(- b/(2a)), or, "at:", f(- 1) = - 3(- 1)^2 - 6(- 1) - 2, or, "at:", f(- 1) = - 3(1) + 6 - 2, or, "at:", f(- 1) = 1))}}}
Vertex: {{{highlight_green(matrix(1,3, "(- 1", ",", "1)"))}}}
Axis of symmetry: {{{highlight_green(x = - 1)}}}