Question 1061026
Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value.

f(x) = -x^2 - 2x + 2

    a. minimum; - 1
    b. maximum; 3
    c. minimum; 3
    d. maximum; - 1
<pre>Leading coefficient is < 0, so function has a {{{highlight_green(matrix(1,2, MAXIMUM, VALUE))}}}
That maximum value occurs at: {{{matrix(1,10, x = - b/(2a), or, at, x = - - 2/(2* - 1), or, at, x = 2/- 2, or, at, x = - 1))}}}
Therefore, maximum value is at f(- 1), and: {{{highlight_green(f(- 1) = - (- 1)^2 - 2(- 1) + 2 = - 1 + 2 + 2 = highlight(3))}}}
We then get: {{{highlight_green(matrix(1,2, CHOICE, "b."))}}} 
That's all.......nothing too COMPLEX!