Question 1061026
Coefficient on the degree-two term is negative one,  {{{-1}}}, so the graph for the parabola is concave downward and has vertex as a MAXIMUM.  


You could convert f into standard form and read the point for the vertex.


{{{-x^2-2x+2}}}
{{{-(x^2+2x-2)}}}
{{{-(x^2+2x+1-1-2)}}}------this step is Completing The Square.
{{{-((x+1)^2-3)}}}
{{{-(x+1)^2+3}}}
Vertex is (-1,3).