<PRE><B>Question 92882</B>
For any number two numbers a and b, the product of (a+b) and (a-b) is always equal to _?_ 
(2+1)*(2-1)=3=2^2-1^2 
(4+2)*(4-2)=12=4^2-2^2 
(3+2)*(3-2)=5=3^2-2^2 
(6+3)*(6-3)=27=6^2-3^2 
(a+b)*(a-b) = a^2-b^2
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You could check this using FOIL.
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Cheers,
Stan H.
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