Question 1060969
margin of error(M.E.) = 4
:
alpha(a) = 1 - (99/100) = 0.01
critical probability(p*) = 1 -(a/2) = 1 - 0.005 = 0.995
critical value(cv) is the value associated with p* = 2.58
:
let n be the sample size, then
:
n = (cv^2 * standard deviation^2) / M.E.^2 = (2.58^2 * 17^2) / 4^2 = 120.23 is approximately 120
:
*****************************************************************
The required sample size is 120
:
Yes. This number of IQ test scores is a fairly large number
:
Note from the Central Limit Theorem when we have the population
standard deviation and a sample size > 30, we can assume a normal
distribution
*****************************************************************