Question 1060947
If you had as {{{y=(x+4)^(1/3)}}} and you switch places for x and y, then this makes  {{{(y+4)^(1/3)=x}}}, and you can try solving for y.


Cube both sides first.
{{{y+4=x^3}}}
{{{y=x^3-4}}}


{{{f^(-1)(x)=x^3-4}}}