Question 1060910
Let {{{ n }}} = number of nickels
Let {{{ d }}} = number of dimes
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(1) {{{ n + d = 59 }}}
(2) {{{ 5n + 10d = 430 }}}
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Subtract (1) from (2)
(2) {{{ n + 2d = 86 }}}
(1) {{{ -n - d = -59 }}}
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{{{ d = 27 }}}
and
(1) {{{ n + d = 59 }}}
(1) {{{ n + 27 = 59 }}}
(1) {{{ n = 32 }}}
{{{ 3 + 2 = 5 }}}
The sum of the digits in number of nickels
is 5
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(2) {{{ 5n + 10d = 430 }}}
(2) {{{ 5*32 + 10*27 = 430 }}}
(2) {{{ 160 + 270 = 430 }}}
(2) {{{ 430 = 430 }}}
OK