Question 92845
{{{((6p-18)/(9p))*((p^2+2p)/(3p-9))}}} Start with the given expression 



{{{((6(p-3))/(9p))*((p^2+2p)/(3p-9))}}} Factor {{{6p-18}}} to get {{{6(p-3)}}}  (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)

 


{{{((6(p-3))/(9p))*((p(p+2))/(3p-9))}}} Factor {{{p^2+2p}}} to get {{{p(p+2)}}}  


{{{((6(p-3))/(9p))*((p(p+2))/(3(p-3)))}}} Factor {{{3p-9}}} to get {{{3(p-3)}}}


{{{((6*cross((p-3)))/(9*cross(p)))*((cross(p)(p+2))/(3*cross((p-3))))}}} Divide and cancel out like terms



{{{(6(p+2))/(9*3))}}} Simplify


{{{(6(p+2))/27)}}} Multiply



{{{(2(p+2))/9)}}} Reduce {{{6/27}}} to {{{2/9}}}




{{{(2p+4)/9)}}} Distribute