Question 1060847
find the slope of the line that goes through the ordered pair (3,-4)(0,2):
Slope is rise/run = (change in y)/(change in x). The slope is called m, so:
m = (y_2-y_1)/(x_2-x_1) = (2-(-4))/(0-3) = -2 
Now we have the value of m: -2.
Next:
Determine the equation of the line that has the point (0,2) on it and the slope of the line m = -2.
We have:
y = mx+b
2 = -2(0)+b
2+2(0) = b
b = 2
y = mx+b is equal to 2 = -2(0)+2
So now we write our findings in slope-intercept form:
y = -2x+2
And we're done.