Question 1060825
x and 3x-8 are the dimensions;
{{{x(3x-8)=35}}}


{{{3x^2-8x-35=0}}}


{{{x=(8+- sqrt(8^2+4*3*35))/(2*3)}}}

{{{x=(8+- sqrt(484))/(2*3)}}}


{{{x=(8+22)/(2*3)}}}

{{{x=(4+11)/3}}}

{{{highlight(x=5)}}}-----WIDTH

Length is 7.