Question 1060712

Solve the equation by completing the square:
5x^2-9x+4=0
<pre>{{{5x^2 - 9x + 4 = 0}}}
{{{5x^2 - 9x = - 4}}} ------ Moving the constant or c to the right side
{{{5x^2/5 - (9/5)x = - 4/5}}} ------ Dividing entire equation by 5 to get a leading coefficient of + 1
{{{x^2 - (9/5)x = - 4/5}}}
{{{x^2 - (9/5)x + (9/10)^2 = - 4/5 + (9/10)^2}}} ------ Taking {{{1/2}}} of b, squaring it, and adding the result to both sides of equation
{{{(x - 9/10)^2 = - 4/5 + 81/100}}}
{{{(x - 9/10)^2 = - 80/100 + 81/100}}}
{{{(x - 9/10)^2 = 1/100}}}
{{{sqrt((x - 9/10)^2) = " "+- sqrt(1/100)}}} ----- Taking the square root of both sides
{{{x - 9/10 = " "+- 1/10}}}
{{{x = 9/10 +- 1/10}}}
{{{highlight_green(matrix(2,5, x = 9/10 + 1/10, "=", 10/10, or, 1, x = 9/10 - 1/10, "=", 8/10, or, 4/5))}}}