Question 1060674
Graphing the region,
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*[illustration dx10.JPG].
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So the actual function to integrate is,
{{{g-f=-x^2+6x-5-2x+5}}}
{{{g-f=-x^2+4x}}}
The limits of integration are {{{x=0}}} and {{{x=4}}} so,
{{{A=int((-x^2+4x),dx,x=0,4)}}}
{{{A=-x^3/3+2x^2+C}}}
{{{A=-4^3/3+2(4)^2}}}
{{{A=-64/3+32}}}
{{{A=-64/3+96/3}}}
{{{A=32/3}}}