Question 1060621
{{{P=2(B+H)=246}}}
{{{B+H=123}}}
and
{{{B=5H}}}
Substituting,
{{{5H+H=123}}}
{{{6H=123}}}
{{{H=123/6}}}
{{{H=41/3}}}
So then,
{{{B=5(41/3)}}}
{{{B=205/3}}}
For a rectangle,
{{{A=BH}}}
{{{A=(41/3)(205/3)}}}

{{{A=8405/9}}}