Question 1060502
Urn1: 2W & 7y
Urn2: 3W & 10y
P1 = P(Urn1 -> white ball)
P2 = P(Urn2 -> white ball)
:
P = P1*P2 (P is the probability that both balls will be white)
Now,
In urn1, there are 9 balls in total, with 2 of them white:
P1 = 2/9
In urn2 there are 13 balls in total, with 3 of them white:
P2 = 3/13
:
P = P1 * P2
P = (2/9)*(3/13)
P = 2/39 or in percentage 5.13%