Question 1060482
<pre><b>
{{{drawing(400,4400/17,-1.5,7,-1.5,4,circle(2,3,.04), circle(5,3/4,.04),
graph(400,4400/17,-1.5,7,-1.5,4), line(2,3,5,3/4),
locate(2.1,3.3,"A(2,3)"), locate(5.1,1,"B(5,y)") )}}}

{{{matrix(1,11,The,length, of,the, segment, from, A(matrix(1,3,x[1],",",y[1])),
to,B(matrix(1,3,x[2],",",y[2])),is,sqrt((x[2]-x[1])^2+(y[2]-y[1])^2))}}}. 

{{{matrix(1,11,The,sum, of, the,ordinates, of, A(matrix(1,3,x[1],",",y[1])),
and,B(matrix(1,3,x[2],",",y[2])),is,y[1]+y[2])}}}. 

{{{"Therefore,"}}}

{{{matrix(1,11,The,length, of,the, segment, from, A(matrix(1,3,2,",",3)),
to,B(matrix(1,3,5,",",y)),is,sqrt((5-2)^2+(y-3)^2))}}}. 

{{{matrix(1,11,The,sum, of, the,ordinates, of, A(matrix(1,3,2,",",3)),
and,B(matrix(1,3,5,",",y)),is,3+y)}}}.

So we set those expressions equal to each other:

{{{sqrt((5-2)^2+(y-3)^2)}}}{{{""=""}}}{{{3+y}}}

Simplify and solve that for y.  If you have trouble, 
tell me about it in the thank-you note form below,
and I'll get back to you by email.  No charge ever.
I'm an old retired math prof, and just do this for fun. :)

Edwin</pre></b>