<PRE><B>Question 1060305</B>
The sum of the squares of two consecutive positive odd integers is 103 more than the product of these two integers.Find the integers 
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1st odd:: 2x-1
2nd odd:: 2x++1
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Equation:
(2x-1)^2 + (2x+1)^2 = (2x-1)(2x+1)+103
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4x^2 - 4x +1 + 4x^2 + 4x + 1 = 4x^2-1+103
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8x^2 +2 = 4x^2+102
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4x^2 = 100
x^2 = 25
x = 5 or x = -5
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1st solution::  2x-1 = 2*5-1 = 9 and 2x+1 = 11
2nd solution:: 2x-1 = 2*-5-1 = -11 and 2x+1 = 2(-5)+1 = -9
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Cheers,
Stan H.
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