Question 1060305
let x and x+2 be the two odd integers
:
x^2 + (x+2)^2 = x * (x+2) + 103
:
x^2 +x^2+4x+4 = x^2 +2x +103:
:
x^2 +2x -99 = 0
:
(x+11) * (x-9) = 0
:
x = -11 or x = 9
:
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There are two solutions
:
9 and 11
:
-11 and -9
:
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