Question 1060242
Joe and Jane together have $91.  If Joe has four-ninths as much as Jane has, who has more money and how much more?
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Equations::
o + a = 91
o = (4/9)a
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Substitute for "o" and solve for "a":
(4/9)a + a = 91
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(13/9)a = 91
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a = (9/13)91
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a = 9*7
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a = 63 yrs (Jane's age)
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Solve for "o"
o = 91-63 
o = 28 yrs (Joe's age)
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Cheers,
Stan H.
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