Question 1060227
{{{36^r=216^(2r)}}}


You have no R in your equation so cannot solve for it.
You could solve for r.


Pick your base.
{{{log((36^r))=log((216^(2r)))}}}


{{{r*log((36))=2r*log((216))}}}


{{{r*log((6^2))=2r*log((6^3))}}}


{{{2r*log((6))=6r*log((6))}}}


{{{2r=6r}}}


{{{0=4r}}}


{{{r=0}}}