<PRE><B>Question 1060201</B>
.
The square poster has sides measuring 2 feet less than the sides of a square sign. If the distance between their area is 52 square feet 
find the lengths of the sides of the poster and the sign.
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&lt;U&gt;Answer&lt;/U&gt;.  12 cm (poster) and 14 cm (sign).


&lt;pre&gt;
x - y = 2,          (1)
x^2 - y^2 = 52.     (2)

====&gt;

x - y = 2,          (1&#39;)
(X+y)*(x-y) = 52.   (2&#39;)

====&gt;

x - y = 2,          (1&#39;&#39;)
x + y = 26.         (2&#39;&#39;)


====&gt;

add (1&#39;&#39;) and (2&#39;&#39;) to get  x = 14.

Then y = 14 - 2 = 12.
&lt;/pre&gt;

Solved.


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