Question 1060037
{{{ .9 = 29 + 49*log(( x+1 )) }}}
{{{ -28.1 = 49*log(( x+1 )) }}}
{{{ -.57347 = log((  x+1 )) }}}
I assume that the base of the log is {{{ 10 }}},
so the other way to write this is:
{{{ 10^(-.57347 ) = x + 1 }}}
{{{ .26701 = x + 1 }}}
{{{ x = -.73299 }}}
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check answer:
{{{ .9 = 29 + 49*log(( -.73299 + 1 )) }}}
{{{ .9 = 29 + 49*log(( .26701 )) }}}
{{{ -28.1 = 49*(-.57347 ) }}}
{{{ -28.1 = -28.10015 }}}
Looks close enough