Question 1059969

Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer
<pre>Let the smallest integer be S
Then the others are: S + 1, S + 2, and S + 3
Equation needed: S + S + 1 + S + 2 = S + 3 + 20
Solve for S, the smallest
Count by 1s after to get the other 3, or add to the preceding to get the next larger